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0=-4.9t^2+38.5t+5.6
We move all terms to the left:
0-(-4.9t^2+38.5t+5.6)=0
We add all the numbers together, and all the variables
-(-4.9t^2+38.5t+5.6)=0
We get rid of parentheses
4.9t^2-38.5t-5.6=0
a = 4.9; b = -38.5; c = -5.6;
Δ = b2-4ac
Δ = -38.52-4·4.9·(-5.6)
Δ = 1592.01
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-38.5)-\sqrt{1592.01}}{2*4.9}=\frac{38.5-\sqrt{1592.01}}{9.8} $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-38.5)+\sqrt{1592.01}}{2*4.9}=\frac{38.5+\sqrt{1592.01}}{9.8} $
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